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**An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:**

A. $\large\frac{1}{2} \mathrm{~kg}$
B. $\large\frac{1}{8} \mathrm{~kg}$
C. $\large\frac{3}{14} \mathrm{~kg}$
D. $\large\frac{7}{9} \mathrm{~kg}$
**Answer: Option B**

## Show Answer

Solution(By Apex Team)

Ratio of Zinc, Copper and Tin is given as,
Z : C : T = 2 : 3 : 1.
Now,
let the first alloy be 12 kg
(taken as 4 kg Zinc, 6 kg Copper and 2 Kg Lead).
Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3.
(taken as 5 kg Copper, 4 kg Tin and 3 Kg Lead.)
Alloys are mixed together to form third alloy. Then the ratio of content in it,
Z : C : T : L = 4 : (6 + 5) : (2 + 4) : 3
Weight of third alloy = 12 + 12 = 24 Kg.
So, weight of the Lead = $\Large\frac{3}{24}=\frac{1}{8}$ kg

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